Java Method to find the given number is even or not without using multiplication, division and modulus operators.

Problem:

Write a short Java method, isEven, that takes an int i and returns true if and only

if i is even. Your method cannot use the multiplication, modulus, or division

operators, however.

Solution:

package com.basics;

import java.util.Scanner;

public class EvenOperations {

static int number;

public static void main(String[] args) {
EvenOperations evenOperations = new EvenOperations();
evenOperations.getTheNumber();
if(evenOperations.isEvenNumber(number)){
System.out.println("the given number is even number");
}
else {
System.out.println("the given number is not even number");
}

}

public void getTheNumber(){
Scanner scanner = new Scanner(System.in);
System.out.println("enter the number");
number = scanner.nextInt();
scanner.close();
}

public boolean isEvenNumber(int number){
boolean isEvenNumber = false;
while(true){
number = number - 2;
if(number == 0){
isEvenNumber = true;
break;
}
else if(number == -1){
break;
}
}
return isEvenNumber;
}

}

Output:

enter the number
1222223
the given number is not even number

enter the number

234

the given number is even number