Java Code to find out the square root of a number

Problem:

Given a number m devise an algorithm to compute its square root.

Solution:

package com.myprograms;

import java.util.Scanner;

public class SquareRootOfNumber {

int n;
public static void main(String[] args) {
SquareRootOfNumber squareRootOfNumber = new SquareRootOfNumber();
squareRootOfNumber.getTheNumber();
squareRootOfNumber.findSquareRoot();

}

public void getTheNumber(){
Scanner s = new Scanner(System.in);
System.out.println("enter the number which need to find the square root");
n = s.nextInt();
s.close();
}

public void findSquareRoot(){
double g1 = 0;
double g2 = n/2;
while(g1-g2 != 0){
g1 = g2;
g2 = (g1+n/g1)/2;
}
System.out.println("the result is: " + g2);
}

}

Output:

enter the number which need to find the square root
225
the result is: 15.0

enter the number which need to find the square root

36

the result is: 6.0

enter the number which need to find the square root

10

the result is: 3.162277660168379